Solution for Longest Common Prefix
05 Aug 2018- 求一组字符串最长的相同前缀
思路如下:
- 先找到这组字符串长度最短的一个
- 遍历这个字符串,同时对比其他字符串相同位置的字符是否相等
- 如果不相等,不再继续比较,直接返回当前字符串开头到当前位置的字串
class Solution(object):
def longestCommonPrefix(self, strs):
"""
:type strs: List[str]
:rtype: str
"""
if not strs:
return ""
if len(strs) == 1:
return strs[0]
sortedStrs = sorted(strs,key=len)
shortest = sortedStrs[0]
if len(shortest) == 0:
return ""
for i, char in enumerate(shortest):
for other in sortedStrs[1:]:
if other[i] != char:
return shortest[:i]
return shortest